Rank: Member
Groups: Member
Joined: 3/23/2006(UTC) Posts: 2
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is it possible to skew an image either horizontal or vertical from a fixed end point
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Rank: Advanced Member
Groups: Member, Administration, Moderator Joined: 8/3/2003(UTC) Posts: 1,070
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Hello, You can implement skew transformation using ApplyMatrixTransform. The basic idea is to specify corners of source image as source points and corner points of skewed image as destination points of transformation. Here is a code sample which illustrates this idea: Code:Aurigma.GraphicsMill.Bitmap bitmap = new Aurigma.GraphicsMill.Bitmap(@"c:/1.jpg");
int skew = 100;
System.Drawing.PointF [] srcPoints = new System.Drawing.PointF[3];
System.Drawing.PointF [] destPoints = new System.Drawing.PointF[3];
srcPoints[0].X = 0;
srcPoints[0].Y = 0;
srcPoints[1].X = bitmap.Width - 1;
srcPoints[1].Y = 0;
srcPoints[2].X = 0;
srcPoints[2].Y = bitmap.Height - 1;
destPoints[0].X = srcPoints[0].X + skew;
destPoints[0].Y = srcPoints[0].Y = 0;
destPoints[1].X = srcPoints[1].X + skew;
destPoints[1].Y = srcPoints[1].Y;
destPoints[2].X = srcPoints[2].X;
destPoints[2].Y = srcPoints[2].Y;
Aurigma.GraphicsMill.Transforms.ApplyMatrixTransform transform = new Aurigma.GraphicsMill.Transforms.ApplyMatrixTransform();
Aurigma.GraphicsMill.Transforms.Matrix matrix = Aurigma.GraphicsMill.Transforms.Matrix.FromAffinePoints(srcPoints, destPoints);
transform.Transform = matrix;
transform.ApplyTransform(bitmap);
bitmap.Save(@"c:/1.png");
Edited by user Thursday, December 20, 2007 4:59:25 PM(UTC)
| Reason: Not specified |
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