Watermark Image

I way trying to change the opacity of one bitmap by using the following code

Dim image as New Aurigma.GrphicMaill.Bitmap("C:\mypic.jpg")

Dim TransBitmap As New Aurigma.GraphicsMill.Bitmap(image.Width, image.Height, Aurigma.GraphicsMill.PixelFormat.Format32bppArgb)

image.Draw(TransBitmap, 0, 0, image.Width, image.Height, Aurigma.GraphicsMill.Transforms.CombineMode.Alpha, 0.3F, Aurigma.GraphicsMill.Transforms.InterpolationMode.HighQuality)

What I would like to do is load this semi transparent image into VObject so that it could be use in the multilayer viewer.

but seems like it doesn't work. Anyone could help out with this please?

Thanks.

Edited by user Sunday, February 3, 2008 10:07:59 AM(UTC)  | Reason: Not specified

Dim image As New Aurigma.GraphicsMill.Bitmap("x:\allformats\24bppRgb.jpg")
image.Channels.AddAlpha(0.7)

Cool..

But is there any way to detect the Alpha Value from a bitmap? Please advice.

Regards

What I want to know is the value we set for the Alpha (example 0.7F)

Hi,

Thanks....

But, for unknown reason, the getPixel only work once

Public Function getAlphaValue(ByVal backgroundImage As Aurigma.GraphicsMill.Bitmap) As Double

Dim _color As System.Drawing.Color

Dim dblRet As Double = 1

Dim myBitmap As Aurigma.GraphicsMill.Bitmap

Try

myBitmap = CType(backgroundImage, Aurigma.GraphicsMill.Bitmap)

_color = myBitmap.GetPixel(10, 10)

dblRet = _color.A / 255

Catch ex As Exception

Finally

dblRet = dblRet * 100

End Try

Return dblRet

End Function

I had a function as above, while, the backgroundImage will be called from a VObject.tag

It works fine while I am working on it. While I save the file (serialized the .tag, and deserialized the bitmap back to the vobject.tag)

then @ this line

_color = myBitmap.GetPixel(10, 10)

I will get the err.Description of

"Object reference not set to an instance of an object."

Please advice.

Edited by user Monday, February 25, 2008 6:29:50 PM(UTC)  | Reason: Not specified

Please advice.

Aurigma.GraphicsMill.Bitmap image = 
	new Aurigma.GraphicsMill.Bitmap("x:/allformats/24bppRgb.jpg");

image.Channels.AddAlpha(0.5f);

Aurigma.GraphicsMill.BitmapData imageData = image.LockBits(0, 0, 1, 1);
try
{
	Aurigma.GraphicsMill.RgbColor pixColor = 
		(Aurigma.GraphicsMill.RgbColor)imageData.GetPixel(0, 0);
	
	System.Windows.Forms.MessageBox.Show(pixColor.ToString());
}
finally
{
	image.UnlockBits(imageData);
}

Hi,

Seems like the issue is still there. It will still goes into same error message on

Aurigma.GraphicsMill.RgbColor pixColor =

(Aurigma.GraphicsMill.RgbColor)imageData.GetPixel(0, 0);

    Public Function getAlphaValue(ByVal backgroundImage As Aurigma.GraphicsMill.Bitmap) As Double
        Dim _color As System.Drawing.Color
        Dim dblRet As Double = 1
        'Dim myBitmap As Aurigma.GraphicsMill.Bitmap
        Dim imageData As Aurigma.GraphicsMill.BitmapData = backgroundImage.LockBits(0, 0, 1, 1)
        Try
            _color = backgroundImage.GetPixel(0, 0)
            dblRet = _color.A / 255
        Catch ex As Exception

        Finally
            backgroundImage.UnlockBits(imageData)
            dblRet = dblRet * 100
        End Try

        Return dblRet

    End Function

Edited by user Monday, February 25, 2008 6:30:10 PM(UTC)  | Reason: Not specified