v3.5 Uploading Thumbnails need filename Options  Email this topic  Watch this topic  Print this topic » Normal Threaded

Previous Topic Next Topic

CharlieK   User Profile View All Posts by User View Thanks		#1 Posted : Thursday, August 23, 2007 9:34:35 AM(UTC)
Rank: Member Groups: Member Joined: 8/23/2007(UTC) Posts: 4		I am running Image Uploader 3.5 and want to upload just a thumbnail/resized image and use the original filename. I have sample code that breaks when the "UploadSourceFile" VALUE="0" Code: For I = 1 To intFileCount ''Get source image and save it to disk SourceFile = Request.Files("SourceFile_" & I) Dim strFileName As String = Path.GetFileName(SourceFile.FileName) Thank you. Edited by user Monday, December 17, 2007 12:24:56 PM(UTC)  | Reason: Not specified
		Charlie

George Ulyanov   User Profile View All Posts by User View Thanks		#2 Posted : Thursday, August 23, 2007 12:26:55 PM(UTC)
Rank: Advanced Member Groups: Member Joined: 7/26/2006(UTC) Posts: 203		Hello, You should set UploadSourceFile property to true. Edited by user Sunday, February 24, 2008 6:55:06 PM(UTC)  | Reason: Not specified
		Best regards, George Ulyanov

CharlieK   User Profile View All Posts by User View Thanks		#3 Posted : Friday, August 24, 2007 12:54:17 AM(UTC)
Rank: Member Groups: Member Joined: 8/23/2007(UTC) Posts: 4		If I set "UploadSourceFile" property to "true" doesn't that defeat the purpose of limiting the upload to only the small thumbnail to save processing time? Wouldn't that upload potentially large image files?
		Charlie

Eugene Kosmin   User Profile View All Posts by User View Thanks		#4 Posted : Monday, August 27, 2007 9:26:23 PM(UTC)
Rank: Advanced Member Groups: Member, Administration, Moderator Joined: 9/19/2006(UTC) Posts: 496 Was thanked: 33 time(s) in 33 post(s)		Hello Charlie, Try to use this: Code: … SourceFile = Request.Files("Thumbnail1_" & I) … Edited by user Monday, February 25, 2008 4:19:52 PM(UTC)  | Reason: Not specified
		Best regards, Eugene Kosmin The Aurigma Development Team

CharlieK   User Profile View All Posts by User View Thanks		#5 Posted : Tuesday, October 9, 2007 9:50:57 PM(UTC)
Rank: Member Groups: Member Joined: 8/23/2007(UTC) Posts: 4		Eugene, Thank you for the suggestion, but I need the original file name, the code you provided would create a name of "Thumbnail1_". Unless I am missing something? Thank you, Edited by user Monday, February 25, 2008 4:20:13 PM(UTC)  | Reason: Not specified
		Charlie

Gavp   User Profile View All Posts by User View Thanks		#6 Posted : Tuesday, October 9, 2007 10:08:20 PM(UTC)
Rank: Member Groups: Member Joined: 10/4/2007(UTC) Posts: 6		Hi, I had a similar problem but I found the filename here in the FileName parameter, so my code is something like this: Code: my $filecount = param("FileCount"); for (my $i = 1; $i <= $filecount; $i++){ my $filename = param("FileName_" . $i); } I hope that helps. Gav Edited by user Monday, February 11, 2008 5:26:52 PM(UTC)  | Reason: Not specified

Users browsing this topic