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Hacim  
#1 Posted : Monday, July 17, 2006 12:51:22 PM(UTC)
Hacim

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Hello, I am having trouble sending php variables to upload.php. Is there a sample script for sending a php variable in the index.php to the upload.php without using a html form?
Alex Makhov  
#2 Posted : Monday, July 17, 2006 4:40:57 PM(UTC)
Alex Makhov

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Hello, There are three ways to send your data to the upload processing script in your case: 1) Add invisible field to the form 2) Use AddField method 3) Change the Action property value to something like this:
Code:
iu.addParam("Action", "upload.php?data1=value1&data2=value2");

Edited by user Monday, February 25, 2008 5:51:59 PM(UTC)  | Reason: Not specified

Sincerely yours, Alex Makhov UserPostedImage Follow Aurigma on Twitter!
Hacim  
#3 Posted : Monday, July 17, 2006 5:00:54 PM(UTC)
Hacim

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Hello and thank you for the reply, i am using the following as suggested and and still having trouble reading the php variable. Do you have any php scripts on this? iu.addParam("Action", "upload.php?data1=$newlastrow");
Fedor  
#4 Posted : Monday, July 17, 2006 7:28:10 PM(UTC)
Fedor

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Quote:
iu.addParam("Action", "upload.php?data1=$newlastrow");
Hmm, I think you should use:
Code:
iu.addParam("Action", "upload.php?data1=");
Also you should use addParam methods only during control initialization. At runtime, you should setAction method:
Code:
getImageUploader("ImageUploaderID").setAction("upload.php?data1=");
Best regards, Fedor Skvortsov
Hacim  
#5 Posted : Monday, July 17, 2006 8:25:20 PM(UTC)
Hacim

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Still not working. Ive added the following:
Code:
iu.addParam ("Action", "upload.php?data1=<% echo $newlastrow%>");

function fullPageupload()
{
imageUploader1=getImageUploader("ImageUploader1").setAction(upload.php?data1=<% echo $newlastrow%>");
}

Edited by user Monday, February 18, 2008 6:19:46 PM(UTC)  | Reason: Not specified

Fedor  
#6 Posted : Monday, July 17, 2006 10:51:26 PM(UTC)
Fedor

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Please post the entire code of you page.
Best regards, Fedor Skvortsov
Fedor  
#7 Posted : Monday, July 17, 2006 11:59:34 PM(UTC)
Fedor

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I am sorry, I am ASP guy mostly, that why I have posted the code using <% %> instead of <?php ?>. Please use this code:
Code:
iu.addParam("Action", "upload.php?data1=<?php echo $newlastrow?>");
Also please note that in the code you have sent me in private communication there are 2 calls of iu.addParam("Action", ...) method. Now that first call will be just ignored.

Edited by user Monday, February 18, 2008 6:19:22 PM(UTC)  | Reason: Not specified

Best regards, Fedor Skvortsov
MOZ  
#8 Posted : Tuesday, July 18, 2006 12:28:38 AM(UTC)
MOZ

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thank you very much thats got it working Regards
MMOZ
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