Image Resolution Question

Private Sub Command1_Click()

    ' Load the file
    Dim objBitmap As New Bitmap
    objBitmap.LoadFromFile "d:\[test files]\Pictures\dog_small.jpg"
    
    ' Specify resolution you want
    objBitmap.HorizontalResolution = 200
    objBitmap.VerticalResolution = 200
       
    ' Obtain resolution of your printer. You can do it using Graphics object of Graphics Mill
    ' Just assign HDC of printer to objGraphics and get HorizontalResolution/VerticalResolution
    ' properties.
    Dim objGraphics As New Graphics
    objGraphics.hDC = Printer.hDC
    
    ' Calculate resolution ratio to resize the bitmap properly
    Dim x As Double, y As Double
    x = objGraphics.HorizontalResolution / objBitmap.HorizontalResolution
    y = objGraphics.VerticalResolution / objBitmap.VerticalResolution
    
    ' Resize the bitmap. To simplify code, retrieve to Resize method percents instead of pixels.
    objBitmap.Unit = UnitPercent
    objBitmap.Transforms.Resize x * 100, y * 100
    
    ' Restore unit back to pixels just in case
    objBitmap.Unit = UnitPixel
    
    ' Print the image
    Printer.Print " "
    objBitmap.DrawOnHdc Printer.hDC
    Printer.EndDoc
    
End Sub

Note, you will not increase the quality by resizing the bitmap. This method can be used to manage the physical size of the image you print, not the quality. To increase quality, you should change printer resolution. And of course, the image should have high resolution initially.

Please let me know if you have any problems with it.

Edited by user Monday, December 24, 2007 5:54:14 PM(UTC)  | Reason: Not specified

objBitmap.Data.ConvertToCmyk

This resolved the error.

Thank you!

Edited by user Monday, December 24, 2007 5:54:41 PM(UTC)  | Reason: Not specified

> the image that prints is much smaller than the 211 x ? pixels that the image was resized to.

The problem is that pixels is a device-dependent unit. It means that you cannot say what length of some number of pixels should be. It depends on the device where you print the image and the device resolution. Resolution is a value which specifies how much pixels are contained in some physical length unit (as usual in one inch). For example, if you print 211 pixel image with 300 DPI, you will get 0.7 inches. If you print with 600 DPI, width will be 0.3 inches. When you browse the image on the monitor, as usual it has 96 DPI, so it will seem you to be 2.1 inches.

To avoid this uncertainty, you should use device-independent units. The most wide-spread device-independent units are points (1/72). These units do not depend on the device resolution. 211 points is always about 3 inches regardless to the DPI.

Please let me know if something is unclear.

> as well as an example of how to keep the ratio of the original image so that it is not distorted?

When you omit one of parameters in Resize method, it should proportionally resize the image and keep the ratio. Do you have problems with it?